1200112132433 has 2 divisors, whose sum is σ = 1200112132434. Its totient is φ = 1200112132432.

The previous prime is 1200112132381. The next prime is 1200112132519. The reversal of 1200112132433 is 3342312110021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1196938838209 + 3173294224 = 1094047^2 + 56332^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1200112132433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1200112132399 and 1200112132408.

It is not a weakly prime, because it can be changed into another prime (1200112132733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600056066216 + 600056066217.

It is an arithmetic number, because the mean of its divisors is an integer number (600056066217).

Almost surely, 2^{1200112132433} is an apocalyptic number.

It is an amenable number.

1200112132433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200112132433 is an equidigital number, since it uses as much as digits as its factorization.

1200112132433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 1200112132433 its reverse (3342312110021), we get a palindrome (4542424242454).

The spelling of 1200112132433 in words is "one trillion, two hundred billion, one hundred twelve million, one hundred thirty-two thousand, four hundred thirty-three".