120011232230033 has 4 divisors (see below), whose sum is σ = 120018846688548. Its totient is φ = 120003617771520.

The previous prime is 120011232230027. The next prime is 120011232230041. The reversal of 120011232230033 is 330032232110021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 62420238819904 + 57590993410129 = 7900648^2 + 7588873^2 .

It is a cyclic number.

It is not a de Polignac number, because 120011232230033 - 2⁴ = 120011232230017 is a prime.

It is a super-2 number, since 2×120011232230033² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120011232229990 and 120011232230008.

It is not an unprimeable number, because it can be changed into a prime (120011232230023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3807205616 + ... + 3807237137.

It is an arithmetic number, because the mean of its divisors is an integer number (30004711672137).

Almost surely, 2^{120011232230033} is an apocalyptic number.

It is an amenable number.

120011232230033 is a deficient number, since it is larger than the sum of its proper divisors (7614458515).

120011232230033 is an equidigital number, since it uses as much as digits as its factorization.

120011232230033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7614458514.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 120011232230033 its reverse (330032232110021), we get a palindrome (450043464340054).

The spelling of 120011232230033 in words is "one hundred twenty trillion, eleven billion, two hundred thirty-two million, two hundred thirty thousand, thirty-three".