1200113000041 has 2 divisors, whose sum is σ = 1200113000042. Its totient is φ = 1200113000040.

The previous prime is 1200112999931. The next prime is 1200113000117. The reversal of 1200113000041 is 1400003110021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1095539022400 + 104573977641 = 1046680^2 + 323379^2 .

It is an emirp because it is prime and its reverse (1400003110021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1200113000041 - 2⁷ = 1200112999913 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1200112999985 and 1200113000030.

It is not a weakly prime, because it can be changed into another prime (1200113006041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600056500020 + 600056500021.

It is an arithmetic number, because the mean of its divisors is an integer number (600056500021).

Almost surely, 2^{1200113000041} is an apocalyptic number.

It is an amenable number.

1200113000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200113000041 is an equidigital number, since it uses as much as digits as its factorization.

1200113000041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 1200113000041 its reverse (1400003110021), we get a palindrome (2600116110062).

The spelling of 1200113000041 in words is "one trillion, two hundred billion, one hundred thirteen million, forty-one", and thus it is an aban number.