Base | Representation |
---|---|
bin | 10001011101101100101… |
… | …110011110111000101011 |
3 | 11020201201102111202002111 |
4 | 101131230232132320223 |
5 | 124130321210000133 |
6 | 2315154424343151 |
7 | 152464043454256 |
oct | 21355456367053 |
9 | 4221642452074 |
10 | 1200120000043 |
11 | 422a714a8988 |
12 | 174711914ab7 |
13 | 8922b411953 |
14 | 4212c44409d |
15 | 213404e11cd |
hex | 1176cb9ee2b |
1200120000043 has 2 divisors, whose sum is σ = 1200120000044. Its totient is φ = 1200120000042.
The previous prime is 1200119999987. The next prime is 1200120000067. The reversal of 1200120000043 is 3400000210021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1200120000043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1200119999978 and 1200120000032.
It is not a weakly prime, because it can be changed into another prime (1200120000083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600060000021 + 600060000022.
It is an arithmetic number, because the mean of its divisors is an integer number (600060000022).
Almost surely, 21200120000043 is an apocalyptic number.
1200120000043 is a deficient number, since it is larger than the sum of its proper divisors (1).
1200120000043 is an equidigital number, since it uses as much as digits as its factorization.
1200120000043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 1200120000043 its reverse (3400000210021), we get a palindrome (4600120210064).
The spelling of 1200120000043 in words is "one trillion, two hundred billion, one hundred twenty million, forty-three", and thus it is an aban number.
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