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1200120000043 is a prime number
BaseRepresentation
bin10001011101101100101…
…110011110111000101011
311020201201102111202002111
4101131230232132320223
5124130321210000133
62315154424343151
7152464043454256
oct21355456367053
94221642452074
101200120000043
11422a714a8988
12174711914ab7
138922b411953
144212c44409d
15213404e11cd
hex1176cb9ee2b

1200120000043 has 2 divisors, whose sum is σ = 1200120000044. Its totient is φ = 1200120000042.

The previous prime is 1200119999987. The next prime is 1200120000067. The reversal of 1200120000043 is 3400000210021.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1200120000043 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1200119999978 and 1200120000032.

It is not a weakly prime, because it can be changed into another prime (1200120000083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600060000021 + 600060000022.

It is an arithmetic number, because the mean of its divisors is an integer number (600060000022).

Almost surely, 21200120000043 is an apocalyptic number.

1200120000043 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200120000043 is an equidigital number, since it uses as much as digits as its factorization.

1200120000043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 1200120000043 its reverse (3400000210021), we get a palindrome (4600120210064).

The spelling of 1200120000043 in words is "one trillion, two hundred billion, one hundred twenty million, forty-three", and thus it is an aban number.