Base | Representation |
---|---|
bin | 10001011101101100101… |
… | …110100100000101010011 |
3 | 11020201201102112211021221 |
4 | 101131230232210011103 |
5 | 124130321211140311 |
6 | 2315154425025511 |
7 | 152464043603320 |
oct | 21355456440523 |
9 | 4221642484257 |
10 | 1200120021331 |
11 | 422a71512980 |
12 | 174711925297 |
13 | 8922b41b54a |
14 | 4212c44bb47 |
15 | 213404e7671 |
hex | 1176cba4153 |
1200120021331 has 32 divisors (see below), whose sum is σ = 1580068638720. Its totient is φ = 883090576800.
The previous prime is 1200120021313. The next prime is 1200120021367. The reversal of 1200120021331 is 1331200210021.
It is a cyclic number.
It is not a de Polignac number, because 1200120021331 - 211 = 1200120019283 is a prime.
It is a super-2 number, since 2×12001200213312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1200120021031) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 863841 + ... + 1773826.
It is an arithmetic number, because the mean of its divisors is an integer number (49377144960).
Almost surely, 21200120021331 is an apocalyptic number.
1200120021331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1200120021331 is a deficient number, since it is larger than the sum of its proper divisors (379948617389).
1200120021331 is a wasteful number, since it uses less digits than its factorization.
1200120021331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2638015.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 1200120021331 its reverse (1331200210021), we get a palindrome (2531320231352).
The spelling of 1200120021331 in words is "one trillion, two hundred billion, one hundred twenty million, twenty-one thousand, three hundred thirty-one".
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