Base | Representation |
---|---|
bin | 10001011101101100101… |
… | …110110111010010000101 |
3 | 11020201201102200211011121 |
4 | 101131230232313102011 |
5 | 124130321221144343 |
6 | 2315154430433541 |
7 | 152464044351514 |
oct | 21355456672205 |
9 | 4221642624147 |
10 | 1200120099973 |
11 | 422a71566a73 |
12 | 1747119628b1 |
13 | 8922b448292 |
14 | 4212c46c67b |
15 | 21340510aed |
hex | 1176cbb7485 |
1200120099973 has 2 divisors, whose sum is σ = 1200120099974. Its totient is φ = 1200120099972.
The previous prime is 1200120099887. The next prime is 1200120100013. The reversal of 1200120099973 is 3799900210021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 786126943044 + 413993156929 = 886638^2 + 643423^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1200120099973 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1200120099173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600060049986 + 600060049987.
It is an arithmetic number, because the mean of its divisors is an integer number (600060049987).
Almost surely, 21200120099973 is an apocalyptic number.
It is an amenable number.
1200120099973 is a deficient number, since it is larger than the sum of its proper divisors (1).
1200120099973 is an equidigital number, since it uses as much as digits as its factorization.
1200120099973 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 61236, while the sum is 43.
The spelling of 1200120099973 in words is "one trillion, two hundred billion, one hundred twenty million, ninety-nine thousand, nine hundred seventy-three".
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