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120012012121093 is a prime number
BaseRepresentation
bin11011010010011001111001…
…010110011110110000000101
3120201221000222110201000022021
4123102121321112132300011
5111212234100100333333
61103124431322203141
734164403352423311
oct3322317126366005
9521830873630267
10120012012121093
113526a899154614
12115631700534b1
1351c7112c46631
14218c880524b41
15dd1bc3ebc82d
hex6d267959ec05

120012012121093 has 2 divisors, whose sum is σ = 120012012121094. Its totient is φ = 120012012121092.

The previous prime is 120012012121087. The next prime is 120012012121121. The reversal of 120012012121093 is 390121210210021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 83214952461729 + 36797059659364 = 9122223^2 + 6066058^2 .

It is a cyclic number.

It is not a de Polignac number, because 120012012121093 - 25 = 120012012121061 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120012012128093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60006006060546 + 60006006060547.

It is an arithmetic number, because the mean of its divisors is an integer number (60006006060547).

Almost surely, 2120012012121093 is an apocalyptic number.

It is an amenable number.

120012012121093 is a deficient number, since it is larger than the sum of its proper divisors (1).

120012012121093 is an equidigital number, since it uses as much as digits as its factorization.

120012012121093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 25.

The spelling of 120012012121093 in words is "one hundred twenty trillion, twelve billion, twelve million, one hundred twenty-one thousand, ninety-three".