Base | Representation |
---|---|
bin | 1010111010100011111101… |
… | …1000100001111101101111 |
3 | 1120111022012101220001112101 |
4 | 2232220333120201331233 |
5 | 3033111430204121312 |
6 | 41305135345315531 |
7 | 2346025655013421 |
oct | 256507730417557 |
9 | 46438171801471 |
10 | 12001202020207 |
11 | 3907754740434 |
12 | 1419ab6335ba7 |
13 | 69092974074a |
14 | 2d6c0b4b6811 |
15 | 15c2a3709a57 |
hex | aea3f621f6f |
12001202020207 has 2 divisors, whose sum is σ = 12001202020208. Its totient is φ = 12001202020206.
The previous prime is 12001202020177. The next prime is 12001202020211. The reversal of 12001202020207 is 70202020210021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12001202020207 - 223 = 12001193631599 is a prime.
It is a super-3 number, since 3×120012020202073 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12001202020237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000601010103 + 6000601010104.
It is an arithmetic number, because the mean of its divisors is an integer number (6000601010104).
Almost surely, 212001202020207 is an apocalyptic number.
12001202020207 is a deficient number, since it is larger than the sum of its proper divisors (1).
12001202020207 is an equidigital number, since it uses as much as digits as its factorization.
12001202020207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 19.
Adding to 12001202020207 its reverse (70202020210021), we get a palindrome (82203222230228).
The spelling of 12001202020207 in words is "twelve trillion, one billion, two hundred two million, twenty thousand, two hundred seven".
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