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120012132300997 is a prime number
BaseRepresentation
bin11011010010011010000000…
…100000111011100011000101
3120201221001021211211210010211
4123102122000200323203011
5111212234321332112442
61103124451254115421
734164406342064116
oct3322320040734305
9521831254753124
10120012132300997
113526a94aa79552
12115631a434bb71
1351c7131b043c1
14218c89248a20d
15dd1bce80b617
hex6d268083b8c5

120012132300997 has 2 divisors, whose sum is σ = 120012132300998. Its totient is φ = 120012132300996.

The previous prime is 120012132300971. The next prime is 120012132301049. The reversal of 120012132300997 is 799003231210021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 64168286481121 + 55843845819876 = 8010511^2 + 7472874^2 .

It is a cyclic number.

It is not a de Polignac number, because 120012132300997 - 27 = 120012132300869 is a prime.

It is a super-5 number, since 5×1200121323009975 (a number of 72 digits) contains 55555 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120012132300967) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60006066150498 + 60006066150499.

It is an arithmetic number, because the mean of its divisors is an integer number (60006066150499).

Almost surely, 2120012132300997 is an apocalyptic number.

It is an amenable number.

120012132300997 is a deficient number, since it is larger than the sum of its proper divisors (1).

120012132300997 is an equidigital number, since it uses as much as digits as its factorization.

120012132300997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40824, while the sum is 40.

The spelling of 120012132300997 in words is "one hundred twenty trillion, twelve billion, one hundred thirty-two million, three hundred thousand, nine hundred ninety-seven".