Base | Representation |
---|---|
bin | 1010111010100100000100… |
… | …1111011110100001001011 |
3 | 1120111022021120120012211222 |
4 | 2232221001033132201023 |
5 | 3033112011144414402 |
6 | 41305142421512255 |
7 | 2346026514031244 |
oct | 256510117364113 |
9 | 46438246505758 |
10 | 12001233201227 |
11 | 39077702a8176 |
12 | 1419b0487268b |
13 | 69093303a15a |
14 | 2d6c116b1ccb |
15 | 15c2a63187a2 |
hex | aea413de84b |
12001233201227 has 2 divisors, whose sum is σ = 12001233201228. Its totient is φ = 12001233201226.
The previous prime is 12001233201197. The next prime is 12001233201239. The reversal of 12001233201227 is 72210233210021.
12001233201227 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12001233201227 - 216 = 12001233135691 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12001233201196 and 12001233201205.
It is not a weakly prime, because it can be changed into another prime (12001233204227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000616600613 + 6000616600614.
It is an arithmetic number, because the mean of its divisors is an integer number (6000616600614).
Almost surely, 212001233201227 is an apocalyptic number.
12001233201227 is a deficient number, since it is larger than the sum of its proper divisors (1).
12001233201227 is an equidigital number, since it uses as much as digits as its factorization.
12001233201227 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 26.
Adding to 12001233201227 its reverse (72210233210021), we get a palindrome (84211466411248).
The spelling of 12001233201227 in words is "twelve trillion, one billion, two hundred thirty-three million, two hundred one thousand, two hundred twenty-seven".
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