1200130001113 has 2 divisors, whose sum is σ = 1200130001114. Its totient is φ = 1200130001112.

The previous prime is 1200130001107. The next prime is 1200130001117. The reversal of 1200130001113 is 3111000310021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1103659504704 + 96470496409 = 1050552^2 + 310597^2 .

It is a cyclic number.

It is not a de Polignac number, because 1200130001113 - 2²⁹ = 1199593130201 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1200130001093 and 1200130001102.

It is not a weakly prime, because it can be changed into another prime (1200130001117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600065000556 + 600065000557.

It is an arithmetic number, because the mean of its divisors is an integer number (600065000557).

Almost surely, 2^{1200130001113} is an apocalyptic number.

It is an amenable number.

1200130001113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200130001113 is an equidigital number, since it uses as much as digits as its factorization.

1200130001113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1200130001113 its reverse (3111000310021), we get a palindrome (4311130311134).

The spelling of 1200130001113 in words is "one trillion, two hundred billion, one hundred thirty million, one thousand, one hundred thirteen".