Base | Representation |
---|---|
bin | 1010111010100100011100… |
… | …1000011111001010010011 |
3 | 1120111022112110112100101102 |
4 | 2232221013020133022103 |
5 | 3033112212000012042 |
6 | 41305200312055015 |
7 | 2346032124054113 |
oct | 256510710371223 |
9 | 46438473470342 |
10 | 12001332032147 |
11 | 3907811070317 |
12 | 1419b3199446b |
13 | 69094a6617a3 |
14 | 2d6c2087b043 |
15 | 15c2aed3bb32 |
hex | aea4721f293 |
12001332032147 has 2 divisors, whose sum is σ = 12001332032148. Its totient is φ = 12001332032146.
The previous prime is 12001332032143. The next prime is 12001332032149. The reversal of 12001332032147 is 74123023310021.
12001332032147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12001332032147 - 22 = 12001332032143 is a prime.
Together with 12001332032149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12001332032143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000666016073 + 6000666016074.
It is an arithmetic number, because the mean of its divisors is an integer number (6000666016074).
Almost surely, 212001332032147 is an apocalyptic number.
12001332032147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12001332032147 is an equidigital number, since it uses as much as digits as its factorization.
12001332032147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 12001332032147 its reverse (74123023310021), we get a palindrome (86124355342168).
The spelling of 12001332032147 in words is "twelve trillion, one billion, three hundred thirty-two million, thirty-two thousand, one hundred forty-seven".
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