Base | Representation |
---|---|
bin | 11011010010011011001110… |
… | …101101110110001111010101 |
3 | 120201221011200021121202002212 |
4 | 123102123032231312033111 |
5 | 111212300013220404343 |
6 | 1103125225403043205 |
7 | 34164454013012144 |
oct | 3322331655661725 |
9 | 521834607552085 |
10 | 120013444309973 |
11 | 35270463629295 |
12 | 115634ab810505 |
13 | 51c72b0885486 |
14 | 218c97881575b |
15 | dd1c59abec18 |
hex | 6d26ceb763d5 |
120013444309973 has 2 divisors, whose sum is σ = 120013444309974. Its totient is φ = 120013444309972.
The previous prime is 120013444309951. The next prime is 120013444310101. The reversal of 120013444309973 is 379903444310021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 72391202923204 + 47622241386769 = 8508302^2 + 6900887^2 .
It is a cyclic number.
It is not a de Polignac number, because 120013444309973 - 26 = 120013444309909 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120013444308973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60006722154986 + 60006722154987.
It is an arithmetic number, because the mean of its divisors is an integer number (60006722154987).
Almost surely, 2120013444309973 is an apocalyptic number.
It is an amenable number.
120013444309973 is a deficient number, since it is larger than the sum of its proper divisors (1).
120013444309973 is an equidigital number, since it uses as much as digits as its factorization.
120013444309973 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1959552, while the sum is 50.
Adding to 120013444309973 its reverse (379903444310021), we get a palindrome (499916888619994).
The spelling of 120013444309973 in words is "one hundred twenty trillion, thirteen billion, four hundred forty-four million, three hundred nine thousand, nine hundred seventy-three".
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