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1200140132407 = 5176092318623
BaseRepresentation
bin10001011101101101111…
…011010010000000110111
311020201202211101120111121
4101131231323102000313
5124130341333214112
62315200424044411
7152464406544226
oct21355573220067
94221684346447
101200140132407
11422a818a96a7
12174718603707
13892326403a8
1442130da4cbd
152134216b407
hex1176ded2037

1200140132407 has 4 divisors (see below), whose sum is σ = 1200142968640. Its totient is φ = 1200137296176.

The previous prime is 1200140132357. The next prime is 1200140132423. The reversal of 1200140132407 is 7042310410021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1200140132407 is a prime.

It is a super-2 number, since 2×12001401324072 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1200140136407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 641703 + ... + 1676920.

It is an arithmetic number, because the mean of its divisors is an integer number (300035742160).

Almost surely, 21200140132407 is an apocalyptic number.

1200140132407 is a deficient number, since it is larger than the sum of its proper divisors (2836233).

1200140132407 is an equidigital number, since it uses as much as digits as its factorization.

1200140132407 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2836232.

The product of its (nonzero) digits is 1344, while the sum is 25.

Adding to 1200140132407 its reverse (7042310410021), we get a palindrome (8242450542428).

The spelling of 1200140132407 in words is "one trillion, two hundred billion, one hundred forty million, one hundred thirty-two thousand, four hundred seven".

Divisors: 1 517609 2318623 1200140132407