Base | Representation |
---|---|
bin | 110111111000101100… |
… | …1111101011011001001 |
3 | 102110202222221122002110 |
4 | 1233301121331123021 |
5 | 3431242120344431 |
6 | 131044521252533 |
7 | 11446031063622 |
oct | 1576131753311 |
9 | 373688848073 |
10 | 120014231241 |
11 | 469969a5283 |
12 | 1b314634149 |
13 | b41812ab18 |
14 | 5b471aca49 |
15 | 31c6367346 |
hex | 1bf167d6c9 |
120014231241 has 4 divisors (see below), whose sum is σ = 160018974992. Its totient is φ = 80009487492.
The previous prime is 120014231179. The next prime is 120014231257. The reversal of 120014231241 is 142132410021.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 120014231241 - 214 = 120014214857 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (120014231641) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20002371871 + ... + 20002371876.
It is an arithmetic number, because the mean of its divisors is an integer number (40004743748).
Almost surely, 2120014231241 is an apocalyptic number.
It is an amenable number.
120014231241 is a deficient number, since it is larger than the sum of its proper divisors (40004743751).
120014231241 is an equidigital number, since it uses as much as digits as its factorization.
120014231241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40004743750.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 120014231241 its reverse (142132410021), we get a palindrome (262146641262).
The spelling of 120014231241 in words is "one hundred twenty billion, fourteen million, two hundred thirty-one thousand, two hundred forty-one".
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