Base | Representation |
---|---|
bin | 11011010010100001011100… |
… | …000010010001101110000111 |
3 | 120201221210212211201001211121 |
4 | 123102201130002101232013 |
5 | 111212402141204021132 |
6 | 1103132251044414411 |
7 | 34165111134220513 |
oct | 3322413402215607 |
9 | 521853784631747 |
10 | 120020110220167 |
11 | 35273274335283 |
12 | 115648500a7407 |
13 | 51c7b038b5c31 |
14 | 218d00bc47143 |
15 | dd1ee9de4497 |
hex | 6d285c091b87 |
120020110220167 has 2 divisors, whose sum is σ = 120020110220168. Its totient is φ = 120020110220166.
The previous prime is 120020110220149. The next prime is 120020110220177. The reversal of 120020110220167 is 761022011020021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120020110220167 - 215 = 120020110187399 is a prime.
It is a super-2 number, since 2×1200201102201672 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120020110220177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60010055110083 + 60010055110084.
It is an arithmetic number, because the mean of its divisors is an integer number (60010055110084).
Almost surely, 2120020110220167 is an apocalyptic number.
120020110220167 is a deficient number, since it is larger than the sum of its proper divisors (1).
120020110220167 is an equidigital number, since it uses as much as digits as its factorization.
120020110220167 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 672, while the sum is 25.
Adding to 120020110220167 its reverse (761022011020021), we get a palindrome (881042121240188).
The spelling of 120020110220167 in words is "one hundred twenty trillion, twenty billion, one hundred ten million, two hundred twenty thousand, one hundred sixty-seven".
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