Base | Representation |
---|---|
bin | 11011010010100010010010… |
… | …010101011011100111010101 |
3 | 120201221220020022220012110021 |
4 | 123102202102111123213111 |
5 | 111212411022412223333 |
6 | 1103132521310225141 |
7 | 34165142535423652 |
oct | 3322422225334725 |
9 | 521856208805407 |
10 | 120021021211093 |
11 | 352736a1594242 |
12 | 11564a651b51b1 |
13 | 51c7c1a55a212 |
14 | 218d096c24c29 |
15 | dd204ed9282d |
hex | 6d289255b9d5 |
120021021211093 has 2 divisors, whose sum is σ = 120021021211094. Its totient is φ = 120021021211092.
The previous prime is 120021021211087. The next prime is 120021021211109. The reversal of 120021021211093 is 390112120120021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 105454455886404 + 14566565324689 = 10269102^2 + 3816617^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120021021211093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120021021211073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60010510605546 + 60010510605547.
It is an arithmetic number, because the mean of its divisors is an integer number (60010510605547).
Almost surely, 2120021021211093 is an apocalyptic number.
It is an amenable number.
120021021211093 is a deficient number, since it is larger than the sum of its proper divisors (1).
120021021211093 is an equidigital number, since it uses as much as digits as its factorization.
120021021211093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 25.
The spelling of 120021021211093 in words is "one hundred twenty trillion, twenty-one billion, twenty-one million, two hundred eleven thousand, ninety-three".
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