Base | Representation |
---|---|
bin | 1010111010100111010110… |
… | …0100011110101001100101 |
3 | 1120111101112202112012202221 |
4 | 2232221311210132221211 |
5 | 3033120310421401041 |
6 | 41305405502432341 |
7 | 2346060334161136 |
oct | 256516544365145 |
9 | 46441482465687 |
10 | 12002111122021 |
11 | 390808091a049 |
12 | 141a10a8926b1 |
13 | 690a42ba2c07 |
14 | 2d6c96121c8d |
15 | 15c3084332d1 |
hex | aea7591ea65 |
12002111122021 has 4 divisors (see below), whose sum is σ = 12002129729100. Its totient is φ = 12002092514944.
The previous prime is 12002111121977. The next prime is 12002111122031. The reversal of 12002111122021 is 12022111120021.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 10573643937796 + 1428467184225 = 3251714^2 + 1195185^2 .
It is a cyclic number.
It is not a de Polignac number, because 12002111122021 - 29 = 12002111121509 is a prime.
It is a super-2 number, since 2×120021111220212 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12002111121986 and 12002111122004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12002111122031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8299906 + ... + 9638083.
It is an arithmetic number, because the mean of its divisors is an integer number (3000532432275).
Almost surely, 212002111122021 is an apocalyptic number.
It is an amenable number.
12002111122021 is a deficient number, since it is larger than the sum of its proper divisors (18607079).
12002111122021 is an equidigital number, since it uses as much as digits as its factorization.
12002111122021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18607078.
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 12002111122021 its reverse (12022111120021), we get a palindrome (24024222242042).
It can be divided in two parts, 1200211 and 1122021, that added together give a palindrome (2322232).
The spelling of 12002111122021 in words is "twelve trillion, two billion, one hundred eleven million, one hundred twenty-two thousand, twenty-one".
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