Base | Representation |
---|---|
bin | 10001011101110010001… |
… | …110001100101001110001 |
3 | 11020201221211222222201112 |
4 | 101131302032030221301 |
5 | 124131013310400144 |
6 | 2315211520443105 |
7 | 152466243242042 |
oct | 21356216145161 |
9 | 4221854888645 |
10 | 1200212200049 |
11 | 423009552135 |
12 | 174738779495 |
13 | 89244554075 |
14 | 4213a7a48c9 |
15 | 2134865499e |
hex | 1177238ca71 |
1200212200049 has 2 divisors, whose sum is σ = 1200212200050. Its totient is φ = 1200212200048.
The previous prime is 1200212199997. The next prime is 1200212200129. The reversal of 1200212200049 is 9400022120021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 757013104225 + 443199095824 = 870065^2 + 665732^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1200212200049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1200212199997 and 1200212200033.
It is not a weakly prime, because it can be changed into another prime (1200212200549) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600106100024 + 600106100025.
It is an arithmetic number, because the mean of its divisors is an integer number (600106100025).
Almost surely, 21200212200049 is an apocalyptic number.
It is an amenable number.
1200212200049 is a deficient number, since it is larger than the sum of its proper divisors (1).
1200212200049 is an equidigital number, since it uses as much as digits as its factorization.
1200212200049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 23.
The spelling of 1200212200049 in words is "one trillion, two hundred billion, two hundred twelve million, two hundred thousand, forty-nine".
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