12002122002113 has 4 divisors (see below), whose sum is σ = 12002451107268. Its totient is φ = 12001792896960.

The previous prime is 12002122002097. The next prime is 12002122002119. The reversal of 12002122002113 is 31120022120021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5929283440144 + 6072838561969 = 2435012^2 + 2464313^2 .

It is a cyclic number.

It is not a de Polignac number, because 12002122002113 - 2⁴ = 12002122002097 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12002122002091 and 12002122002100.

It is not an unprimeable number, because it can be changed into a prime (12002122002119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 164497868 + ... + 164570813.

It is an arithmetic number, because the mean of its divisors is an integer number (3000612776817).

Almost surely, 2^{12002122002113} is an apocalyptic number.

It is an amenable number.

12002122002113 is a deficient number, since it is larger than the sum of its proper divisors (329105155).

12002122002113 is an equidigital number, since it uses as much as digits as its factorization.

12002122002113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 329105154.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 12002122002113 its reverse (31120022120021), we get a palindrome (43122144122134).

The spelling of 12002122002113 in words is "twelve trillion, two billion, one hundred twenty-two million, two thousand, one hundred thirteen".