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12002123201112 = 23321131598285509
BaseRepresentation
bin1010111010100111011001…
…0010100011101001011000
31120111101120121020220011200
42232221312102203221120
53033120322014413422
641305411013354200
72346060541640142
oct256516622435130
946441517226150
1012002123201112
11390808771a270
12141a112938960
13690a45541bc5
142d6c97987c92
1515c30951c2ac
hexaea764a3a58

12002123201112 has 192 divisors, whose sum is σ = 37225139328000. Its totient is φ = 3460028140800.

The previous prime is 12002123201083. The next prime is 12002123201119. The reversal of 12002123201112 is 21110232120021.

12002123201112 is a `hidden beast` number, since 1 + 20 + 0 + 212 + 320 + 1 + 112 = 666.

12002123201112 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×120021232011122 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12002123201119) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2694187 + ... + 5591322.

It is an arithmetic number, because the mean of its divisors is an integer number (193880934000).

Almost surely, 212002123201112 is an apocalyptic number.

12002123201112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

12002123201112 is an abundant number, since it is smaller than the sum of its proper divisors (25223016126888).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12002123201112 is a wasteful number, since it uses less digits than its factorization.

12002123201112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8285622 (or 8285615 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 12002123201112 its reverse (21110232120021), we get a palindrome (33112355321133).

The spelling of 12002123201112 in words is "twelve trillion, two billion, one hundred twenty-three million, two hundred one thousand, one hundred twelve".