Base | Representation |
---|---|
bin | 1010111010100111011001… |
… | …0110100001100110110101 |
3 | 1120111101120200012202002101 |
4 | 2232221312112201212311 |
5 | 3033120322301210313 |
6 | 41305411051542101 |
7 | 2346060553531642 |
oct | 256516626414665 |
9 | 46441520182071 |
10 | 12002124241333 |
11 | 390808826a856 |
12 | 141a11315a931 |
13 | 690a45817515 |
14 | 2d6c97b78dc9 |
15 | 15c3096755dd |
hex | aea765a19b5 |
12002124241333 has 2 divisors, whose sum is σ = 12002124241334. Its totient is φ = 12002124241332.
The previous prime is 12002124241259. The next prime is 12002124241337. The reversal of 12002124241333 is 33314242120021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10386484959249 + 1615639282084 = 3222807^2 + 1271078^2 .
It is a cyclic number.
It is not a de Polignac number, because 12002124241333 - 241 = 9803100985781 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12002124241337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001062120666 + 6001062120667.
It is an arithmetic number, because the mean of its divisors is an integer number (6001062120667).
Almost surely, 212002124241333 is an apocalyptic number.
It is an amenable number.
12002124241333 is a deficient number, since it is larger than the sum of its proper divisors (1).
12002124241333 is an equidigital number, since it uses as much as digits as its factorization.
12002124241333 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 12002124241333 its reverse (33314242120021), we get a palindrome (45316366361354).
The spelling of 12002124241333 in words is "twelve trillion, two billion, one hundred twenty-four million, two hundred forty-one thousand, three hundred thirty-three".
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