Base | Representation |
---|---|
bin | 110111111000111010… |
… | …1010110010111110111 |
3 | 102110210111110102022021 |
4 | 1233301311112113313 |
5 | 3431300440130234 |
6 | 131045335214011 |
7 | 11446146110035 |
oct | 1576165262767 |
9 | 373714412267 |
10 | 120021411319 |
11 | 4699aa59827 |
12 | 1b316b17307 |
13 | b419772ca4 |
14 | 5b4811b555 |
15 | 31c6cd49b4 |
hex | 1bf1d565f7 |
120021411319 has 2 divisors, whose sum is σ = 120021411320. Its totient is φ = 120021411318.
The previous prime is 120021411271. The next prime is 120021411329. The reversal of 120021411319 is 913114120021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120021411319 - 215 = 120021378551 is a prime.
It is a super-2 number, since 2×1200214113192 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 120021411293 and 120021411302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120021411329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60010705659 + 60010705660.
It is an arithmetic number, because the mean of its divisors is an integer number (60010705660).
Almost surely, 2120021411319 is an apocalyptic number.
120021411319 is a deficient number, since it is larger than the sum of its proper divisors (1).
120021411319 is an equidigital number, since it uses as much as digits as its factorization.
120021411319 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 25.
The spelling of 120021411319 in words is "one hundred twenty billion, twenty-one million, four hundred eleven thousand, three hundred nineteen".
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