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12002201220003 = 34000733740001
BaseRepresentation
bin1010111010100111101011…
…1100001011001110100011
31120111101210001001122222020
42232221322330023032203
53033121002003020003
641305422441512523
72346062510042361
oct256517274131643
946441701048866
1012002201220003
113908117767a95
12141a134aa2743
13690a5875a627
142d6ca4096631
1515c3112cdd53
hexaea7af0b3a3

12002201220003 has 4 divisors (see below), whose sum is σ = 16002934960008. Its totient is φ = 8001467480000.

The previous prime is 12002201220001. The next prime is 12002201220131. The reversal of 12002201220003 is 30002210220021.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12002201220003 - 21 = 12002201220001 is a prime.

It is not an unprimeable number, because it can be changed into a prime (12002201220001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2000366869998 + ... + 2000366870003.

It is an arithmetic number, because the mean of its divisors is an integer number (4000733740002).

Almost surely, 212002201220003 is an apocalyptic number.

12002201220003 is a deficient number, since it is larger than the sum of its proper divisors (4000733740005).

12002201220003 is an equidigital number, since it uses as much as digits as its factorization.

12002201220003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4000733740004.

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 12002201220003 its reverse (30002210220021), we get a palindrome (42004411440024).

The spelling of 12002201220003 in words is "twelve trillion, two billion, two hundred one million, two hundred twenty thousand, three".

Divisors: 1 3 4000733740001 12002201220003