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12002315311499 = 76691565043071
BaseRepresentation
bin1010111010101000000110…
…1111011001100110001011
31120111102001222202010002012
42232222001233121212023
53033121220204431444
641305442035130135
72346065363564552
oct256520157314613
946442058663065
1012002315311499
113908176103687
12141a16714394b
13690a762960a6
142d6cb52b4d99
1515c31b318b9e
hexaea81bd998b

12002315311499 has 4 divisors (see below), whose sum is σ = 12003880362240. Its totient is φ = 12000750260760.

The previous prime is 12002315311477. The next prime is 12002315311523. The reversal of 12002315311499 is 99411351320021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12002315311499 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12002315311439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 782513867 + ... + 782529204.

It is an arithmetic number, because the mean of its divisors is an integer number (3000970090560).

Almost surely, 212002315311499 is an apocalyptic number.

12002315311499 is a deficient number, since it is larger than the sum of its proper divisors (1565050741).

12002315311499 is an equidigital number, since it uses as much as digits as its factorization.

12002315311499 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1565050740.

The product of its (nonzero) digits is 58320, while the sum is 41.

The spelling of 12002315311499 in words is "twelve trillion, two billion, three hundred fifteen million, three hundred eleven thousand, four hundred ninety-nine".

Divisors: 1 7669 1565043071 12002315311499