Base | Representation |
---|---|
bin | 10001011101110011111… |
… | …101010010010010110111 |
3 | 11020202000212210111100120 |
4 | 101131303331102102313 |
5 | 124131043234234033 |
6 | 2315214440543023 |
7 | 152500045620144 |
oct | 21356375222267 |
9 | 4222025714316 |
10 | 1200241321143 |
11 | 423023a32257 |
12 | 174746481a73 |
13 | 8924a5abc97 |
14 | 421405c53cb |
15 | 2134aea81b3 |
hex | 11773f524b7 |
1200241321143 has 4 divisors (see below), whose sum is σ = 1600321761528. Its totient is φ = 800160880760.
The previous prime is 1200241321079. The next prime is 1200241321231. The reversal of 1200241321143 is 3411231420021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1200241321143 - 26 = 1200241321079 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1200241321343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200040220188 + ... + 200040220193.
It is an arithmetic number, because the mean of its divisors is an integer number (400080440382).
Almost surely, 21200241321143 is an apocalyptic number.
1200241321143 is a deficient number, since it is larger than the sum of its proper divisors (400080440385).
1200241321143 is an equidigital number, since it uses as much as digits as its factorization.
1200241321143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 400080440384.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 1200241321143 its reverse (3411231420021), we get a palindrome (4611472741164).
The spelling of 1200241321143 in words is "one trillion, two hundred billion, two hundred forty-one million, three hundred twenty-one thousand, one hundred forty-three".
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