Base | Representation |
---|---|
bin | 1010111010101000111010… |
… | …1011101001100111100011 |
3 | 1120111102122010021222220101 |
4 | 2232222032223221213203 |
5 | 3033122141300313410 |
6 | 41305515352523231 |
7 | 2346103641230143 |
oct | 256521653514743 |
9 | 46442563258811 |
10 | 12002532432355 |
11 | 390827771a803 |
12 | 141a2079b0517 |
13 | 690aac26617a |
14 | 2d6cd6072923 |
15 | 15c330405d3a |
hex | aea8eae99e3 |
12002532432355 has 4 divisors (see below), whose sum is σ = 14403038918832. Its totient is φ = 9602025945880.
The previous prime is 12002532432353. The next prime is 12002532432361. The reversal of 12002532432355 is 55323423520021.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 12002532432355 - 21 = 12002532432353 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12002532432353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1200253243231 + ... + 1200253243240.
It is an arithmetic number, because the mean of its divisors is an integer number (3600759729708).
Almost surely, 212002532432355 is an apocalyptic number.
12002532432355 is a deficient number, since it is larger than the sum of its proper divisors (2400506486477).
12002532432355 is an equidigital number, since it uses as much as digits as its factorization.
12002532432355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2400506486476.
The product of its (nonzero) digits is 216000, while the sum is 37.
Adding to 12002532432355 its reverse (55323423520021), we get a palindrome (67325955952376).
The spelling of 12002532432355 in words is "twelve trillion, two billion, five hundred thirty-two million, four hundred thirty-two thousand, three hundred fifty-five".
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