Base | Representation |
---|---|
bin | 10001011101111000001… |
… | …010111111000011100001 |
3 | 11020202012210211102121211 |
4 | 101131320022333003201 |
5 | 124131214334134332 |
6 | 2315225444150121 |
7 | 152501564560621 |
oct | 21357012770341 |
9 | 4222183742554 |
10 | 1200312021217 |
11 | 42305a931271 |
12 | 174766098341 |
13 | 8925c13434a |
14 | 42149b4a881 |
15 | 213522c1447 |
hex | 117782bf0e1 |
1200312021217 has 2 divisors, whose sum is σ = 1200312021218. Its totient is φ = 1200312021216.
The previous prime is 1200312021179. The next prime is 1200312021241. The reversal of 1200312021217 is 7121202130021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1197763891776 + 2548129441 = 1094424^2 + 50479^2 .
It is a cyclic number.
It is not a de Polignac number, because 1200312021217 - 223 = 1200303632609 is a prime.
It is a super-2 number, since 2×12003120212172 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1200312021247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600156010608 + 600156010609.
It is an arithmetic number, because the mean of its divisors is an integer number (600156010609).
Almost surely, 21200312021217 is an apocalyptic number.
It is an amenable number.
1200312021217 is a deficient number, since it is larger than the sum of its proper divisors (1).
1200312021217 is an equidigital number, since it uses as much as digits as its factorization.
1200312021217 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 336, while the sum is 22.
Adding to 1200312021217 its reverse (7121202130021), we get a palindrome (8321514151238).
The spelling of 1200312021217 in words is "one trillion, two hundred billion, three hundred twelve million, twenty-one thousand, two hundred seventeen".
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