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12003121221000 = 23353713671076133
BaseRepresentation
bin1010111010101011000111…
…0001101100110110001000
31120111111011011012120002020
42232222301301230312020
53033124343013033000
641310054024404440
72346124350653130
oct256526161546610
946444134176066
1012003121221000
11390854a010398
12141a351016720
13690b74237a10
142d6d5033bac0
1515c366e5bba0
hexaeab1c6cd88

12003121221000 has 1024 divisors, whose sum is σ = 47224819998720. Its totient is φ = 2471009587200.

The previous prime is 12003121220977. The next prime is 12003121221037. The reversal of 12003121221000 is 12212130021.

12003121221000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 1957133934 + ... + 1957140066.

It is an arithmetic number, because the mean of its divisors is an integer number (46117988280).

Almost surely, 212003121221000 is an apocalyptic number.

12003121221000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12003121221000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (23612409999360).

12003121221000 is an abundant number, since it is smaller than the sum of its proper divisors (35221698777720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12003121221000 is a wasteful number, since it uses less digits than its factorization.

12003121221000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6351 (or 6337 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 12003121221000 its reverse (12212130021), we get a palindrome (12015333351021).

The spelling of 12003121221000 in words is "twelve trillion, three billion, one hundred twenty-one million, two hundred twenty-one thousand".