1200312312231 has 4 divisors (see below), whose sum is σ = 1600416416312. Its totient is φ = 800208208152.

The previous prime is 1200312312197. The next prime is 1200312312253. The reversal of 1200312312231 is 1322132130021.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1200312312231 - 2⁶ = 1200312312167 is a prime.

It is a super-2 number, since 2×1200312312231² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1200312312198 and 1200312312207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1200312312271) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200052052036 + ... + 200052052041.

It is an arithmetic number, because the mean of its divisors is an integer number (400104104078).

Almost surely, 2^{1200312312231} is an apocalyptic number.

1200312312231 is a deficient number, since it is larger than the sum of its proper divisors (400104104081).

1200312312231 is an equidigital number, since it uses as much as digits as its factorization.

1200312312231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 400104104080.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 1200312312231 its reverse (1322132130021), we get a palindrome (2522444442252).

The spelling of 1200312312231 in words is "one trillion, two hundred billion, three hundred twelve million, three hundred twelve thousand, two hundred thirty-one".