1200313314241 has 2 divisors, whose sum is σ = 1200313314242. Its totient is φ = 1200313314240.

The previous prime is 1200313314229. The next prime is 1200313314257. The reversal of 1200313314241 is 1424133130021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1128542904241 + 71770410000 = 1062329^2 + 267900^2 .

It is a cyclic number.

It is not a de Polignac number, because 1200313314241 - 2⁵ = 1200313314209 is a prime.

It is a super-2 number, since 2×1200313314241² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1200313314281) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600156657120 + 600156657121.

It is an arithmetic number, because the mean of its divisors is an integer number (600156657121).

Almost surely, 2^{1200313314241} is an apocalyptic number.

It is an amenable number.

1200313314241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200313314241 is an equidigital number, since it uses as much as digits as its factorization.

1200313314241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1200313314241 its reverse (1424133130021), we get a palindrome (2624446444262).

The spelling of 1200313314241 in words is "one trillion, two hundred billion, three hundred thirteen million, three hundred fourteen thousand, two hundred forty-one".