12003134134031 has 4 divisors (see below), whose sum is σ = 12009049924200. Its totient is φ = 11997218343864.

The previous prime is 12003134134001. The next prime is 12003134134049. The reversal of 12003134134031 is 13043143130021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12003134134031 - 2¹⁴ = 12003134117647 is a prime.

It is a super-2 number, since 2×12003134134031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12003134134001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2957892041 + ... + 2957896098.

It is an arithmetic number, because the mean of its divisors is an integer number (3002262481050).

Almost surely, 2^{12003134134031} is an apocalyptic number.

12003134134031 is a deficient number, since it is larger than the sum of its proper divisors (5915790169).

12003134134031 is an equidigital number, since it uses as much as digits as its factorization.

12003134134031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5915790168.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 12003134134031 its reverse (13043143130021), we get a palindrome (25046277264052).

The spelling of 12003134134031 in words is "twelve trillion, three billion, one hundred thirty-four million, one hundred thirty-four thousand, thirty-one".