1200320133211 has 4 divisors (see below), whose sum is σ = 1212694567672. Its totient is φ = 1187945698752.

The previous prime is 1200320133191. The next prime is 1200320133241. The reversal of 1200320133211 is 1123310230021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1200320133211 is a prime.

It is a super-3 number, since 3×1200320133211³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1200320133241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6187217085 + ... + 6187217278.

It is an arithmetic number, because the mean of its divisors is an integer number (303173641918).

Almost surely, 2^{1200320133211} is an apocalyptic number.

1200320133211 is a deficient number, since it is larger than the sum of its proper divisors (12374434461).

1200320133211 is an equidigital number, since it uses as much as digits as its factorization.

1200320133211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12374434460.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1200320133211 its reverse (1123310230021), we get a palindrome (2323630363232).

The spelling of 1200320133211 in words is "one trillion, two hundred billion, three hundred twenty million, one hundred thirty-three thousand, two hundred eleven".