12003231441113 has 4 divisors (see below), whose sum is σ = 13094434299408. Its totient is φ = 10912028582820.

The previous prime is 12003231441101. The next prime is 12003231441119. The reversal of 12003231441113 is 31114413230021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12003231441113 - 2¹² = 12003231437017 is a prime.

It is not an unprimeable number, because it can be changed into a prime (12003231441119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 545601429131 + ... + 545601429152.

It is an arithmetic number, because the mean of its divisors is an integer number (3273608574852).

Almost surely, 2^{12003231441113} is an apocalyptic number.

It is an amenable number.

12003231441113 is a deficient number, since it is larger than the sum of its proper divisors (1091202858295).

12003231441113 is a wasteful number, since it uses less digits than its factorization.

12003231441113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1091202858294.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 12003231441113 its reverse (31114413230021), we get a palindrome (43117644671134).

The spelling of 12003231441113 in words is "twelve trillion, three billion, two hundred thirty-one million, four hundred forty-one thousand, one hundred thirteen".