12003233149 has 2 divisors, whose sum is σ = 12003233150. Its totient is φ = 12003233148.

The previous prime is 12003233119. The next prime is 12003233167. The reversal of 12003233149 is 94133230021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11988717049 + 14516100 = 109493^2 + 3810^2 .

It is a cyclic number.

It is not a de Polignac number, because 12003233149 - 2⁵ = 12003233117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12003233119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001616574 + 6001616575.

It is an arithmetic number, because the mean of its divisors is an integer number (6001616575).

Almost surely, 2^12003233149 is an apocalyptic number.

It is an amenable number.

12003233149 is a deficient number, since it is larger than the sum of its proper divisors (1).

12003233149 is an equidigital number, since it uses as much as digits as its factorization.

12003233149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 28.

It can be divided in two parts, 120032 and 33149, that added together give a triangular number (153181 = T₅₅₃).

The spelling of 12003233149 in words is "twelve billion, three million, two hundred thirty-three thousand, one hundred forty-nine".