Search a number
-
+
12003324343 = 36433294901
BaseRepresentation
bin10110010110111010…
…00011000110110111
31010222112101001111021
423023131003012313
5144040322334333
65303024522011
7603311400463
oct131335030667
933875331437
1012003324343
1150aa62226a
1223aba80307
131193a599aa
1481c2454a3
154a3bca82d
hex2cb7431b7

12003324343 has 4 divisors (see below), whose sum is σ = 12006622888. Its totient is φ = 12000025800.

The previous prime is 12003324337. The next prime is 12003324353. The reversal of 12003324343 is 34342330021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12003324343 - 29 = 12003323831 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12003324353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1643808 + ... + 1651093.

It is an arithmetic number, because the mean of its divisors is an integer number (3001655722).

Almost surely, 212003324343 is an apocalyptic number.

12003324343 is a deficient number, since it is larger than the sum of its proper divisors (3298545).

12003324343 is an equidigital number, since it uses as much as digits as its factorization.

12003324343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3298544.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 12003324343 its reverse (34342330021), we get a palindrome (46345654364).

The spelling of 12003324343 in words is "twelve billion, three million, three hundred twenty-four thousand, three hundred forty-three".

Divisors: 1 3643 3294901 12003324343