Base | Representation |
---|---|
bin | 10001011101111010000… |
… | …010110001110001100111 |
3 | 11020202021222220212021200 |
4 | 101131322002301301213 |
5 | 124131300404032403 |
6 | 2315232525213543 |
7 | 152502425521335 |
oct | 21357202616147 |
9 | 4222258825250 |
10 | 1200343424103 |
11 | 42307662a76a |
12 | 1747747012b3 |
13 | 892657aaa35 |
14 | 4214dda2b55 |
15 | 21354e25ca3 |
hex | 1177a0b1c67 |
1200343424103 has 6 divisors (see below), whose sum is σ = 1733829390384. Its totient is φ = 800228949396.
The previous prime is 1200343424099. The next prime is 1200343424113. The reversal of 1200343424103 is 3014243430021.
1200343424103 is a `hidden beast` number, since 1 + 200 + 3 + 4 + 3 + 42 + 410 + 3 = 666.
It is not a de Polignac number, because 1200343424103 - 22 = 1200343424099 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1200343424113) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 66685745775 + ... + 66685745792.
It is an arithmetic number, because the mean of its divisors is an integer number (288971565064).
Almost surely, 21200343424103 is an apocalyptic number.
1200343424103 is a deficient number, since it is larger than the sum of its proper divisors (533485966281).
1200343424103 is a wasteful number, since it uses less digits than its factorization.
1200343424103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 133371491573 (or 133371491570 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 1200343424103 its reverse (3014243430021), we get a palindrome (4214586854124).
The spelling of 1200343424103 in words is "one trillion, two hundred billion, three hundred forty-three million, four hundred twenty-four thousand, one hundred three".
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