Base | Representation |
---|---|
bin | 110111111001010100… |
… | …1001110101001001011 |
3 | 102110211110001100202121 |
4 | 1233302221032221023 |
5 | 3431312430324042 |
6 | 131050542512111 |
7 | 11446402521502 |
oct | 1576251165113 |
9 | 373743040677 |
10 | 120035011147 |
11 | 469a76a8557 |
12 | 1b31b595637 |
13 | b41c52521c |
14 | 5b49c5b839 |
15 | 31c80be367 |
hex | 1bf2a4ea4b |
120035011147 has 2 divisors, whose sum is σ = 120035011148. Its totient is φ = 120035011146.
The previous prime is 120035011091. The next prime is 120035011169. The reversal of 120035011147 is 741110530021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120035011147 - 223 = 120026622539 is a prime.
It is not a weakly prime, because it can be changed into another prime (120035311147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60017505573 + 60017505574.
It is an arithmetic number, because the mean of its divisors is an integer number (60017505574).
Almost surely, 2120035011147 is an apocalyptic number.
120035011147 is a deficient number, since it is larger than the sum of its proper divisors (1).
120035011147 is an equidigital number, since it uses as much as digits as its factorization.
120035011147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 840, while the sum is 25.
Adding to 120035011147 its reverse (741110530021), we get a palindrome (861145541168).
The spelling of 120035011147 in words is "one hundred twenty billion, thirty-five million, eleven thousand, one hundred forty-seven".
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