131050542512111 has 2 divisors, whose sum is σ = 131050542512112. Its totient is φ = 131050542512110.

The previous prime is 131050542512107. The next prime is 131050542512173. The reversal of 131050542512111 is 111215245050131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131050542512111 - 2² = 131050542512107 is a prime.

It is a super-2 number, since 2×131050542512111² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131050542512711) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65525271256055 + 65525271256056.

It is an arithmetic number, because the mean of its divisors is an integer number (65525271256056).

Almost surely, 2^{131050542512111} is an apocalyptic number.

131050542512111 is a deficient number, since it is larger than the sum of its proper divisors (1).

131050542512111 is an equidigital number, since it uses as much as digits as its factorization.

131050542512111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6000, while the sum is 32.

Adding to 131050542512111 its reverse (111215245050131), we get a palindrome (242265787562242).

The spelling of 131050542512111 in words is "one hundred thirty-one trillion, fifty billion, five hundred forty-two million, five hundred twelve thousand, one hundred eleven".