Base | Representation |
---|---|
bin | 10001011101111010110… |
… | …000001101100110000011 |
3 | 11020202022211022222022122 |
4 | 101131322300031212003 |
5 | 124131311431201111 |
6 | 2315234032354455 |
7 | 152502631665533 |
oct | 21357260154603 |
9 | 4222284288278 |
10 | 1200355334531 |
11 | 4230823251a1 |
12 | 1747786a5a2b |
13 | 892680bb022 |
14 | 421517c34c3 |
15 | 21355ec9cdb |
hex | 1177ac0d983 |
1200355334531 has 2 divisors, whose sum is σ = 1200355334532. Its totient is φ = 1200355334530.
The previous prime is 1200355334501. The next prime is 1200355334543. The reversal of 1200355334531 is 1354335530021.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (1354335530021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1200355334531 - 214 = 1200355318147 is a prime.
It is a super-2 number, since 2×12003553345312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1200355334491 and 1200355334500.
It is not a weakly prime, because it can be changed into another prime (1200355334501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600177667265 + 600177667266.
It is an arithmetic number, because the mean of its divisors is an integer number (600177667266).
Almost surely, 21200355334531 is an apocalyptic number.
1200355334531 is a deficient number, since it is larger than the sum of its proper divisors (1).
1200355334531 is an equidigital number, since it uses as much as digits as its factorization.
1200355334531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81000, while the sum is 35.
The spelling of 1200355334531 in words is "one trillion, two hundred billion, three hundred fifty-five million, three hundred thirty-four thousand, five hundred thirty-one".
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