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12003943477 is a prime number
BaseRepresentation
bin10110010110111110…
…11010010000110101
31010222120112111210011
423023133122100311
5144041002142402
65303050100221
7603316556521
oct131337322065
933876474704
1012003943477
1150aaa05449
1223b011a671
131193c15746
1481c366d81
154a3c9ded7
hex2cb7da435

12003943477 has 2 divisors, whose sum is σ = 12003943478. Its totient is φ = 12003943476.

The previous prime is 12003943463. The next prime is 12003943507. The reversal of 12003943477 is 77434930021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7709893636 + 4294049841 = 87806^2 + 65529^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12003943477 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12003943877) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001971738 + 6001971739.

It is an arithmetic number, because the mean of its divisors is an integer number (6001971739).

Almost surely, 212003943477 is an apocalyptic number.

It is an amenable number.

12003943477 is a deficient number, since it is larger than the sum of its proper divisors (1).

12003943477 is an equidigital number, since it uses as much as digits as its factorization.

12003943477 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 127008, while the sum is 40.

The spelling of 12003943477 in words is "twelve billion, three million, nine hundred forty-three thousand, four hundred seventy-seven".