1200404311441 has 4 divisors (see below), whose sum is σ = 1200458594032. Its totient is φ = 1200350028852.

The previous prime is 1200404311411. The next prime is 1200404311459. The reversal of 1200404311441 is 1441134040021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1200404311441 - 2²¹ = 1200402214289 is a prime.

It is a super-2 number, since 2×1200404311441² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1200404311411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27108111 + ... + 27152356.

It is an arithmetic number, because the mean of its divisors is an integer number (300114648508).

Almost surely, 2^{1200404311441} is an apocalyptic number.

It is an amenable number.

1200404311441 is a deficient number, since it is larger than the sum of its proper divisors (54282591).

1200404311441 is an equidigital number, since it uses as much as digits as its factorization.

1200404311441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54282590.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 1200404311441 its reverse (1441134040021), we get a palindrome (2641538351462).

The spelling of 1200404311441 in words is "one trillion, two hundred billion, four hundred four million, three hundred eleven thousand, four hundred forty-one".