Base | Representation |
---|---|
bin | 11011010010110101000000… |
… | …111110010011011100011111 |
3 | 120202000211010211001212100011 |
4 | 123102311000332103130133 |
5 | 111213223214020432203 |
6 | 1103150045001344051 |
7 | 34166454063160330 |
oct | 3322650076233437 |
9 | 522024124055304 |
10 | 120041131030303 |
11 | 3528118100103a |
12 | 11568937a98027 |
13 | 51c9aa3905b22 |
14 | 2190043936287 |
15 | dd282a5a276d |
hex | 6d2d40f9371f |
120041131030303 has 8 divisors (see below), whose sum is σ = 137415876995072. Its totient is φ = 102722888305656.
The previous prime is 120041131030297. The next prime is 120041131030313. The reversal of 120041131030303 is 303030131140021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 120041131030303 - 221 = 120041128933151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120041131030313) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14125805475 + ... + 14125813972.
It is an arithmetic number, because the mean of its divisors is an integer number (17176984624384).
Almost surely, 2120041131030303 is an apocalyptic number.
120041131030303 is a deficient number, since it is larger than the sum of its proper divisors (17374745964769).
120041131030303 is an equidigital number, since it uses as much as digits as its factorization.
120041131030303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28251620061.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 120041131030303 its reverse (303030131140021), we get a palindrome (423071262170324).
The spelling of 120041131030303 in words is "one hundred twenty trillion, forty-one billion, one hundred thirty-one million, thirty thousand, three hundred three".
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