120041402001433 has 4 divisors (see below), whose sum is σ = 130954256728848. Its totient is φ = 109128547274020.

The previous prime is 120041402001431. The next prime is 120041402001481. The reversal of 120041402001433 is 334100204140021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 120041402001433 - 2¹ = 120041402001431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120041402001398 and 120041402001407.

It is not an unprimeable number, because it can be changed into a prime (120041402001431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5456427363691 + ... + 5456427363712.

It is an arithmetic number, because the mean of its divisors is an integer number (32738564182212).

Almost surely, 2^{120041402001433} is an apocalyptic number.

It is an amenable number.

120041402001433 is a deficient number, since it is larger than the sum of its proper divisors (10912854727415).

120041402001433 is a wasteful number, since it uses less digits than its factorization.

120041402001433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10912854727414.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 120041402001433 its reverse (334100204140021), we get a palindrome (454141606141454).

The spelling of 120041402001433 in words is "one hundred twenty trillion, forty-one billion, four hundred two million, one thousand, four hundred thirty-three".