120041434251405 has 48 divisors (see below), whose sum is σ = 208196472369600. Its totient is φ = 63983748697344.

The previous prime is 120041434251371. The next prime is 120041434251499. The reversal of 120041434251405 is 504152434140021.

120041434251405 is a `hidden beast` number, since 1 + 20 + 0 + 4 + 143 + 42 + 51 + 405 = 666.

It is not a de Polignac number, because 120041434251405 - 2⁶ = 120041434251341 is a prime.

It is a super-3 number, since 3×120041434251405³ (a number of 43 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 120041434251405.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1317657546 + ... + 1317748644.

It is an arithmetic number, because the mean of its divisors is an integer number (4337426507700).

Almost surely, 2^{120041434251405} is an apocalyptic number.

120041434251405 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

120041434251405 is a deficient number, since it is larger than the sum of its proper divisors (88155038118195).

120041434251405 is a wasteful number, since it uses less digits than its factorization.

120041434251405 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 108330 (or 108327 counting only the distinct ones).

The product of its (nonzero) digits is 76800, while the sum is 36.

Adding to 120041434251405 its reverse (504152434140021), we get a palindrome (624193868391426).

The spelling of 120041434251405 in words is "one hundred twenty trillion, forty-one billion, four hundred thirty-four million, two hundred fifty-one thousand, four hundred five".