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1200420012413 is a prime number
BaseRepresentation
bin10001011101111110100…
…110111100000101111101
311020202111100000221200202
4101131332212330011331
5124131430010344123
62315244302533245
7152504345515016
oct21357646740575
94222440027622
101200420012413
11423105890696
12174796297225
138927861526b
144215a21c00d
152135ba03a28
hex1177e9bc17d

1200420012413 has 2 divisors, whose sum is σ = 1200420012414. Its totient is φ = 1200420012412.

The previous prime is 1200420012377. The next prime is 1200420012439. The reversal of 1200420012413 is 3142100240021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1047466277764 + 152953734649 = 1023458^2 + 391093^2 .

It is a cyclic number.

It is not a de Polignac number, because 1200420012413 - 28 = 1200420012157 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1200420012313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600210006206 + 600210006207.

It is an arithmetic number, because the mean of its divisors is an integer number (600210006207).

Almost surely, 21200420012413 is an apocalyptic number.

It is an amenable number.

1200420012413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200420012413 is an equidigital number, since it uses as much as digits as its factorization.

1200420012413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 1200420012413 its reverse (3142100240021), we get a palindrome (4342520252434).

The spelling of 1200420012413 in words is "one trillion, two hundred billion, four hundred twenty million, twelve thousand, four hundred thirteen".