Base | Representation |
---|---|
bin | 10001011110000000000… |
… | …011101011110001110101 |
3 | 11020202120000210011021020 |
4 | 101132000003223301311 |
5 | 124132002221344411 |
6 | 2315250532011353 |
7 | 152505062255106 |
oct | 21360003536165 |
9 | 4222500704236 |
10 | 1200444324981 |
11 | 423118587020 |
12 | 1747a2460b59 |
13 | 892806785b5 |
14 | 4215d54a3ad |
15 | 2135dc07606 |
hex | 117800ebc75 |
1200444324981 has 16 divisors (see below), whose sum is σ = 1746122572800. Its totient is φ = 727532958320.
The previous prime is 1200444324949. The next prime is 1200444324991. The reversal of 1200444324981 is 1894234440021.
It is a cyclic number.
It is not a de Polignac number, because 1200444324981 - 25 = 1200444324949 is a prime.
It is a super-2 number, since 2×12004443249812 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1200444324991) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3270946 + ... + 3619388.
It is an arithmetic number, because the mean of its divisors is an integer number (109132660800).
Almost surely, 21200444324981 is an apocalyptic number.
1200444324981 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
1200444324981 is a deficient number, since it is larger than the sum of its proper divisors (545678247819).
1200444324981 is a wasteful number, since it uses less digits than its factorization.
1200444324981 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 452856.
The product of its (nonzero) digits is 221184, while the sum is 42.
The spelling of 1200444324981 in words is "one trillion, two hundred billion, four hundred forty-four million, three hundred twenty-four thousand, nine hundred eighty-one".
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