12005136473 has 4 divisors (see below), whose sum is σ = 13096512528. Its totient is φ = 10913760420.

The previous prime is 12005136457. The next prime is 12005136509. The reversal of 12005136473 is 37463150021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12005136473 - 2⁴ = 12005136457 is a prime.

It is not an unprimeable number, because it can be changed into a prime (12005136413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 545688011 + ... + 545688032.

It is an arithmetic number, because the mean of its divisors is an integer number (3274128132).

Almost surely, 2^12005136473 is an apocalyptic number.

It is an amenable number.

12005136473 is a deficient number, since it is larger than the sum of its proper divisors (1091376055).

12005136473 is a wasteful number, since it uses less digits than its factorization.

12005136473 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1091376054.

The product of its (nonzero) digits is 15120, while the sum is 32.

Adding to 12005136473 its reverse (37463150021), we get a palindrome (49468286494).

The spelling of 12005136473 in words is "twelve billion, five million, one hundred thirty-six thousand, four hundred seventy-three".