Base | Representation |
---|---|
bin | 110111111001110111… |
… | …0111111111111100001 |
3 | 102110212201110121000121 |
4 | 1233303232333333201 |
5 | 3431332121114332 |
6 | 131052434520241 |
7 | 11450014136353 |
oct | 1576356777741 |
9 | 373781417017 |
10 | 120053301217 |
11 | 46a06a60113 |
12 | 1b325736081 |
13 | b42325a255 |
14 | 5b4c45d0d3 |
15 | 31c99d3797 |
hex | 1bf3bbffe1 |
120053301217 has 2 divisors, whose sum is σ = 120053301218. Its totient is φ = 120053301216.
The previous prime is 120053301187. The next prime is 120053301223. The reversal of 120053301217 is 712103350021.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 70981747776 + 49071553441 = 266424^2 + 221521^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120053301217 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 120053301191 and 120053301200.
It is not a weakly prime, because it can be changed into another prime (120053301287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60026650608 + 60026650609.
It is an arithmetic number, because the mean of its divisors is an integer number (60026650609).
Almost surely, 2120053301217 is an apocalyptic number.
It is an amenable number.
120053301217 is a deficient number, since it is larger than the sum of its proper divisors (1).
120053301217 is an equidigital number, since it uses as much as digits as its factorization.
120053301217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1260, while the sum is 25.
Adding to 120053301217 its reverse (712103350021), we get a palindrome (832156651238).
The spelling of 120053301217 in words is "one hundred twenty billion, fifty-three million, three hundred one thousand, two hundred seventeen".
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