Base | Representation |
---|---|
bin | 110111111001111011… |
… | …1000011010011101111 |
3 | 102110212212102211101221 |
4 | 1233303313003103233 |
5 | 3431333141140301 |
6 | 131052552044211 |
7 | 11450041110166 |
oct | 1576367032357 |
9 | 373785384357 |
10 | 120055411951 |
11 | 46a08171a22 |
12 | 1b326393667 |
13 | b423818bc7 |
14 | 5b4c84c3dd |
15 | 31c9c9dda1 |
hex | 1bf3dc34ef |
120055411951 has 2 divisors, whose sum is σ = 120055411952. Its totient is φ = 120055411950.
The previous prime is 120055411909. The next prime is 120055412027. The reversal of 120055411951 is 159114550021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120055411951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120055411351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60027705975 + 60027705976.
It is an arithmetic number, because the mean of its divisors is an integer number (60027705976).
Almost surely, 2120055411951 is an apocalyptic number.
120055411951 is a deficient number, since it is larger than the sum of its proper divisors (1).
120055411951 is an equidigital number, since it uses as much as digits as its factorization.
120055411951 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9000, while the sum is 34.
Adding to 120055411951 its reverse (159114550021), we get a palindrome (279169961972).
The spelling of 120055411951 in words is "one hundred twenty billion, fifty-five million, four hundred eleven thousand, nine hundred fifty-one".
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